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Mekhanik [1.2K]
3 years ago
5

After their car broke down the Lambert brothers had to walk to work. John walked .27 miles, Bill walked .6 miles, and Larry walk

ed .2 miles. Who walked the furthest?
I am leaning toward John, but am iffy about whether or not it is a "trick" question.
Mathematics
2 answers:
mote1985 [20]3 years ago
4 0
.27=0.27, .6=0.6, .2=0.2

The biggest number of all three is 0.6, so the one who walked the furthest is Bill.
krok68 [10]3 years ago
3 0
Bill walked the most. Put the decimals into percentages. .27 is 27%, .6 is 60%, and .2 is 20%, so Bill with 60% walked the furthest. 
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Answer:

The 99% confidence interval is   165.776  <  \mu <  180.224  

Step-by-step explanation:

From the question we are told that

     The sample size is  n  = 100

     The sample mean is  \=  x  =  173 \  days

      The population standard deviation is  \sigma =  28 \ days  

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

      E = 2.58  *  \frac{28 }{\sqrt{100} }

=>    E = 7.224

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>     173 -7.224  <  \mu < 173 + 7.224    

=>     165.776  <  \mu < 180.224  

     

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