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Ad libitum [116K]

3 years ago

10

In the triangle below, find the measurements of the unknown angles. a 75 • A. 75 1059 B. 40°. 80° O c. 50, 10° O D. 25°, 50 O E

35°. 70

1 answer:

Deffense [45]3 years ago

5 0

answer:

explanation:

hope it helps!

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WHAT IS X³-27 SIMPLIFIED

Eduardwww [97]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>(</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>)</u><u>³</u><u> </u><u>-</u><u> </u><u>9</u><u>x</u><u>(</u><u>3</u><u> </u><u>-</u><u> </u><u>x</u><u>)</u>

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

$= {x}^{3} - {3}^{3}$

From trinomial expansion:

${(x - y)}^{3} = (x - y)(x - y)(x - y) \\$

open first two brackets to get a quadratic equation:

${(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)$

expand further:

${(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}$

take y to be 3, then substitute:

$( {x}^{3} - 3^3) = {(x - 3)}^{3} - 9x(3 - x)$

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3 years ago

How long will it take a person to walk from Toronto to

storchak [24]

Answer:

About 947 hours, walking at 5 km (3 miles)/hour.

Walking 8 hours /day [at that pace you would need to be an Olympic Athlete to keep up the pace] it will take about four months.

Walk slower, it will take longer.

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