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kati45 [8]
3 years ago
8

............................HELP PLSS

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
5 0

Answer:

72.34

Step-by-step explanation:

Calculated the value

Natali5045456 [20]3 years ago
4 0

936.24 cm

Step-by-step explanation:

First of all find the cm or m value of that inches value as it'll become harder to tackle with inches... then find the radius in inches... then find the area

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The Sum of three decimal numbers is 6 what could the numbers be? Chose all that apply
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Answer:

it is B

Step-by-step explanation:

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What are the domain, range, and midline of the function f(x)=1/2cos(1/4x)-1?​
erma4kov [3.2K]

Your function is: f(x)=\frac{1}{2}\cos \Big( \frac{1}{4x}\Big) -1

Domain: $(-\infty, +\infty)-\{ 0 \}$ or $R-\{ 0 \}$

Range: $[-\frac{3}{2}, -\frac{1}{2}]$

Midline: $y=-1$

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How do I find (10x + 2) °
Deffense [45]

Answer:

multiply 10 with the value given for x and add 2 to the result

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3 years ago
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Reduce 7y + 2y 2 - 7 by 3 - 4y.
NARA [144]

Answer:

D. 2y^2+11y-10.

Step-by-step explanation:

Given:

We need to reduce 7y+2y^2-7 by 3-4y

Solution:

To reduce the equation means we need to subtract the one equation from other.

First we will arrange the equation n proper format we get;

2y^2+7y-7  ⇒ equation 1

Also Arranging other equation we get;

-4y+3   ⇒ equation 2

Now we will subtract equation 2 from equation 1 we get;

(2y^2+7y-7)-(-4y+3)

Now Applying distributive property for the sign we get;

2y^2+7y-7+4y-3

Now Arranging the like terms we get;

2y2+7y-+4y-7-3\\\\2y^2+11y-10

Hence the reduce form of the given equation is 2y^2+11y-10.

7 0
3 years ago
1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
3 years ago
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