Ф = 3π/4. Transform it into Rectangular (or Cartesian) form .
The coordinates of Ф are x ,y in rectangular form ==> so:
tan(Ф) = y/x and y=x . tan(Ф) ==> y= x. tan(3π/4). we know that tan(3π/4)= - 1
Hence y = - x
Answer:
390=W 195=L Area=76050
Step-by-step explanation:
You have two lengths and one width for your perimeter
P= 2L + W
you are given your perimiter 780
780= 2L + W
To solve for your maximum Width
780-2L=w
Area is L * W
A= (780-2L)*L
A= 780L - 2L^2
the derivitive of the Area
A' = 780-4L =0
add 4L to both sides
780=4L
divide by 4 on both sides
195=L
Bring back 780-2L=W and plug in what you now know is L
780-2(195)=W
780-390=W
390=W
P - (-3) would turn into p+3.
So we have
p - (-3) = 2
become
p + 3 = 2
To isolate p, we need to move that "+3" over. To do this, we subtract 3 from both sides. Subtraction is the opposite (or inverse) of addition, which is why this works
p+3 = 2
p+3-3 = 2-3 ... subtract 3 from both sides
p+0 = -1
p = -1
So the final answer is p = -1
Answer:
Value of x = -1 and y = -4
Step-by-step explanation:
BC = 3 (given)
BC = AD ( opposite sides of a parallelogram are equal)
∴ AD = 3
AD = x - y (given)
∴ 3 = x - y
3 + y = x -------- (1)
CD = 2 (given)
CD = AB (opposite sides of a parallelogram are equal)
∴ AB = 2
AB = 2x - y (given)
∴ 2 = 2x - y ----------- (2)
Putting the value of x in (1) To (2)
2 = 2(3+y) - y
2 = 6 + 2y - y
2 = 6 + y
2 - 6 = y
-4 = y
Now, substitute the value of y in (1)
x = 3 + y
x = 3 + (-4)
x = 3 - 4
x = -1
Therefore, the value of x = -1 and y = -4.
<u>Cross-checking</u>
2x - y = 2
2*-1 - (-4) = 2
-2 -(-4) = 2
-2 + 4 = 2
2 = 2
LHS = RHS
x - y = 3
-1 -(-4) = 3
-1+4 = 3
3 = 3
LHS = RHS
Thus verified
Hope u understand
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Answer:
The temperature of the 5th day was 3°C
Step-by-step explanation:
Mean temperature of the first 4 days = 8°C
Note that:
Mean = Sum of temperatures ÷ number of days
∴ 8 = sum of temperature ÷ 4
Therefore the sum of the first 4 days = 32
Let the temperature of the next day (the fifth day) be m
Hence,
sum of the temperatures of first 5 days = 32 + m - - - - (1)
Next, the sum of the first 5 days can be calculated from the given average of the first 5 days as follows:
Mean temperature of the first 5 days = 7
Now, you will notice that equation (1) = equation (2)
∴ 32 + m = 35
m = 35 - 32 = 3
therefore, the temperature of the 5th day was 3°C
