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sergij07 [2.7K]
3 years ago
6

A bank loaned out ​$18,000​, part of it at the rate of 9% per year and the rest at 19% per year. If the interest received in one

year totaled ​$​3000, how much was loaned at 9%
How much of the ​$18,000 did the bank loan out at 9%?
Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0
X * 0.09 + (18000-x)*0.19= 3000
x*(-0.1) + 3420 = 3000
x = -420/(-0.1)
x = 4200

The bank loaned out $4,200 at 9%
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The difference between the annual and semi-annual compound interest on a sum of money is Rs 482 at the rate of 20 % per annum fo
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→ successive Rate of 20% for 2 Years = 2*20 + (20*20/100) = 40 + 4 = 44%.

And, when interest is compounded semi - Annually,

→ Rate = (20/2) = 10% .

→ Time = 2 * 2 = 4 Years.

So,

→ successive Rate of 10% for 4 Years = (2*10 + (10*10/100) = 21% Now, => 21*2 + (21*21/100) = 42 + 4.41 = 46.41% .

A/q,

→ (46.41%) - 44% = 482

→ 1% = (482/2.41)

→ 100% = (482/2.41) * 100 = Rs.20000 (Ans.)

Step-by-step explanation:

Answer from Gauth math

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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