If the function is
and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.
Given function is
and f(4) − f(1) = f '(c)(4 − 1).
In this question we have to apply the mean value theorem, which says that given a secant line between points A and B, there is at least a point C that belongs to the curve and the derivative of that curve exists.
We begin by calculating f(2) and f(5):
f(2)=
f(2)=1
f(5)=
f(5)=1
And the slope of the function:
(x)=
(c)=0
Now,

=-2
=0
-2 is not equal to 0. So there is not any answer.
Hence if the function is
and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.
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Answer:
0
Step-by-step explanation:
8/5 divided by 0 = 0
Answer:
y = 1/2x + 5
sorry no explanation but pls give brainliest
Answer:
36 units
Step-by-step explanation:
to do this you must first find the lengths of all the sides with pythagorean theorem
for a to b you use
3^2 + 4^2 = c^2
9 + 16 = c^2
25 = c^2
c = 5
5 is one of the lengths
b to c uses the same equation
so
5 is another one of the lengths
for d to c your equation is
5^2 + 12^2 = c^2
25 + 144 = c^2
169 = c^2
13 is another of the lengths
d to a has the same length as c to d so there is another 13 unit length
so
5 + 5 + 13 + 13 is your equation to find the perimeter
5 + 5 + 13 + 13 = 36
that is your answer
Answer:
Limit is 18
Step-by-step explanation:
Using direct substitution
5x+ 2x+ 4 = 5(2) + 2(2)+ 4 = 10+ 4+ 4= 18