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natulia [17]
3 years ago
15

The ratio of pizza to nachos sold during A-lunch is 4 to 3. There was 48 nachos sold. What number of pizzas sold during A-lunch?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0

Answer:

64 pizzas

Step-by-step explanation:

4:3 * x:48

x resembles the amount of pizzas sold,

what times 3 = 48?

x=16

4 * 16 is 64

64 pizzas were sold

* Let me know if you have any questions*

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Haily paid $13 for 1 and 3/7 kf of sliced salami. What was the cost per kilogram of salami?
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4 0
4 years ago
) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection
RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

C_{(m,n)} = \frac{m!}{n!(m-n)!}

In this question, m = 18, n = 9. So the total number of possibilities is:

T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715

The probability is the number of desired possibilities divided by the number of total possibilities. So

P = \frac{715}{48620} = 0.015 = 1.5%

The probability the he or she will answer correctly is 1.5%

3 0
3 years ago
What is the following product 3/x^2 4/x^3??
Alborosie

9514 1404 393

Answer:

  12/x^5

Step-by-step explanation:

The fractions are multiplied in the usual way. The applicable rule of exponents is ...

  (x^a)(x^b) = x^(a+b)

__

  \dfrac{3}{x^2}\cdot\dfrac{4}{x^3}=\dfrac{3\cdot4}{x^2\cdot x^3}=\dfrac{12}{x^{2+3}}=\boxed{\dfrac{12}{x^5}}

7 0
3 years ago
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