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MrRa [10]
3 years ago
5

Calculate the [H3O+] of 0.35 M solution of benzoic acid HC7H3O2

Chemistry
1 answer:
solmaris [256]3 years ago
5 0

Answer:

[H_3O^+]=4.7x10^{-3}M

Explanation:

Hello there!

In this case, since the ionization of benzoic acid is:

HC_7H_3O_2+H_2O\rightleftharpoons C_7H_3O_2^-+H_3O^+

Whereas the corresponding equilibrium expression is:

Ka=\frac{[C_7H_3O_2^-][H_3O^+]}{[HC_7H_3O_2]}

Now, we insert the acidic equilibrium constant and the reaction extent x, to write:

6.3x10^{-5}=\frac{x^2}{0.35M}

Thus, by solving for x, we obtain:

x=\sqrt{6.3x10^{-5}*0.35}\\\\x=4.7x10^{-3}M

Which is also:

x=4.7x10^{-3}M

Best regards!

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Answer:

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Explanation:

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7 0
3 years ago
Read 2 more answers
In the following net ionic equation, identify each reactant as either a Bronsted-Lowry acid or a Bronsted-Lowry base. HCN(aq) H2
vfiekz [6]

Answer:

Explanation:

The definition of acids and bases by Arrhenius Theory  was modified and extended by  Bronsted-Lowry.

Bronsted-Lowry defined acid as a molecule or ion which donates a proton while a base is a molecule or ions that accepts the proton. This definition can be extended to include acid -base titrations in non-aqueous solutions.

In this theory, the reaction of an acid with a base constitutes a transfer of a proton from the acid to the base.

From the given information:

\mathsf{HCN _{(aq)} + H_2O_{(l)} \to CN^{-}_{(aq)} + H_3O_{(aq)}}

From above:

We will see that HCN releases an H⁺ ion, thus it is a Bronsted-Lowry acid

H_2O accepts the H⁺ ion ,thus it is a Bronsted-Lowry base.

The formula of the reactant that acts as a proton donor is <u>HCN</u>

The formula of the reactant that acts as a proton acceptor is <u>H2O</u>

8 0
3 years ago
COURSES GROUPS RESOURCES GRADE REPORT Q OOO try: 913322 4 Honors Chemistry Tests/Quizzes ormulas Reactions Quiz Questic Question
Aleks04 [339]

Answer:

2.02 × 10²³ atoms

Explanation:

Step 1: Calculate the moles corresponding to 37.8 g of cadmium

To convert mass to moles, we need a conversion factor: the molar mass. The molar mass of cadmium is 112.41 g/mol.

37.8 g × 1 mol/112.41 g = 0.336 mol

Step 2: Calculate the number of atoms in 0.336 moles of cadmium

To convert moles to atoms, we need a conversion factor: Avogadro's number. In 1 mole of atoms of cadmium, there are 6.02 × 10²³ atoms of cadmium.

0.336 mol × 6.02 × 10²³ atoms/1 mol = 2.02 × 10²³ atoms

6 0
3 years ago
Which of the following is an example of a physical change ?
inessss [21]
A. A piece of Iron being heated until it melts
Because it goes from solid to liquid.
A physical change is changing from solid to a liquid, a liquid to a gas, a gas to a liquid, a liquid to a solid, a solid to a gas, or a gas to a solid.
3 0
3 years ago
What is a substance which allows the red blood cells to carry oxygen and iron.
bogdanovich [222]
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8 0
3 years ago
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