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Elina [12.6K]
2 years ago
8

¿En qué condiciones puede decir que el oro es un líquido? 15 points

Chemistry
1 answer:
11111nata11111 [884]2 years ago
4 0

El oro solido se derrite y convierte en liquido a la temperatura de 1,948°F o de 1064.444°C. A esa temperatura o mas se condera liquido el oro

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Cobalt-59 is a stable isotope and cobalt-60 is an unstable or radioactive isotope. These two isotopes differ in the number of -
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Cobalt-59 and Cobalt-60 differ in that they have different mass number which means they have different number of neutrons. Isotopes are atoms of the same element with similar atomic number but different mass number. Cobalt-60, has a number of uses, which includes, being used to irradiate food sources as a method of preserving food, used in industrial radiography to detect structural flaws in metal parts among other uses. 
7 0
3 years ago
Jen makes a Venn diagram to compare active transport and passive transport.
Oksanka [162]

Answer:

moves molecules

Explanation:

I did this one yesterday! Active transport moves low to high concentration and passive does the opposite so C and D are not an option. Active transport requires energy and Passive Transport does not so it has to be A.!

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3 years ago
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2 years ago
oth hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opene
Ksju [112]

Answer: Odor of ammonia would we detect first on the other side of the room.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

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\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{17.031}{34.1}}

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Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.

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3 years ago
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cricket20 [7]
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
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Moles=14.5g / 58.14g/mol
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Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
6 0
2 years ago
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