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motikmotik
3 years ago
5

Find the molar mass of Ca(NO3)2

Chemistry
2 answers:
spayn [35]3 years ago
6 0

 The  molar  mass  of  Ca(NO₃)2  is 164 g/mol


<u><em> Explanation</em></u>

Ca(NO₃)2   is  made  up of   Ca  , N  and  O  elements

Therefore the  molar mass  of Ca(NO₃)2   =  molar  mass  of Ca +  molar  mass  of N +molar mass of O


from periodic table the molar mass of  Ca is 40 g/mol

for  N  =  14 g/ mol

 for  O = 16 g/mol. since they are  3 atoms  of O in  Ca(NO₃)2  the  molar mass = 16  x3 = 48  g/mol


The molar  mass   of Ca(NO₃)2 = 40 g/mo  + [(14  g/mol + 48 g/mol) 2] =164g/mol


sdas [7]3 years ago
6 0

Answer:164.10 to be exact

Explanation:

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4 years ago
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Atmosphere pressure is about 100000 Pa. Calculate the force of the Atmosphere on a person whose Surface area is 2.0m
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Answer:

The force of the atmosphere 200 KN.

Explanation:

Pressure is the ratio of force applied to the area  to which the force is applied.

i.e Pressure = \frac{Force}{Area}

But, Pressure = 100000 pa (100000 N/ m^{2}), and surface area = 2.0 m^{2}

Thus,

100000 = \frac{Force}{2.0}

⇒ Force = 100000 x 2.0

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7 0
3 years ago
Write your question here (Keep it simple and clear to get the best answer) calculate the atomic weight of a metal when 125ml of
lana [24]

Answer:

The answer to your question is 24.32 g

Explanation:

Data

Atomic weight = ?

HCl volume = 125 ml

Molarity = 0.2

mass of metal = 0.304 g

Balanced chemical equation

                       M + 2HCl   ⇒  MCl₂  +  H₂

Process

1.- Calculate the moles of HCl

Molarity = moles / volume (L)

- Solve for moles

  moles = Molarity  x volume

  moles = 0.2 x 0.125

             = 0.025

2.- Calculate the moles of the Metal

                1 mol of M ----------------- 2 moles of HCl

                x                ----------------- 0.025 moles of HCl

                x = (0.025 x 1) / 2

                x = 0.0125 moles of HCl

3.- Calculate the atomic weight of the metal

                atomic weight ---------------- 1 mol

               0.304 g             ---------------0.0125 moles

               Atomic weight = (1 x 0.304) / 0.0125

               Atomic weight = 24.32 g    

             

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Electronegativities of the elements Be, Mg, Ca, and Sr follow a specific trend within their group. Based on this trend, the atom
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A certain liquid X has a normal freezing point of 7.60 °C and a freezing point depression constant K= 6.90 °C-kg-mol. Calculate
Dmitry [639]

<u>Answer:</u> The freezing point of solution is -5.11°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:

NaCl(aq.)\rightarrow Na^{+}(aq.)+Cl^-(aq.)

The total number of ions present in the solution are 2.

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (NaCl) = 7.57 g

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Putting values in above equation, we get:

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To calculate the depression in freezing point, we use the equation:

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Putting values in above equation, we get:

\Delta T=2\times 6.90^oC/m.g\times 0.370m\\\\\Delta T=5.11^oC

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\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 5.11 °C

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Putting values in above equation, we get:

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Hence, the freezing point of solution is -5.11°C

7 0
4 years ago
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