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2 years ago

(4x + 3y)^2 please tell me the wander ✌️

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

8 0

Answer:

16x^2+24xy+9y^2

Step-by-step explanation:

16x^2+24xy+9y^2

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Tell wether the triangle with the given side is a right triangle.

BlackZzzverrR [31]

Answer:

Number 4 is a right triangle whether 3 isnt.

Step-by-step explanation:

I just know this because a right triangle is always gonna have a 90 degree angle whether that number 3 doesnt have one

8 0

3 years ago

Graph the proportional relationship, y = 5x.

kap26 [50]

Answer:

Hope the graph below helps.

Step-by-step explanation:

5 0

2 years ago

Which expressions are equivalent to -56z + 28.

NeX [460]

Answer:

B and C

Step-by-step explanation:

(-7)•8z = -56z

(-4)•(-7)=28

and

40•(-1.4)= -56z

40•0.7= 28

5 0

2 years ago

The polynomial equation x^3+x^2=-9x-9 has complex roots +/-3i What is the other root? Use a graphing calculator and a system of

Ierofanga [76]

For this case what you can do is factorize the <span>polynomial equation</span>, which would be left like follows
x ^ 3 + x ^ 2 + 9x + 9 = 0
(x + 1) (x ^ 2 + 9) = 0
Resolving, we have that the missing root is
x = -1
Answer
x=-1

7 0

3 years ago

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

$k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2$

6 0

1 year ago

(4x + 3y)^2 please tell me the wander ✌️​

(4x + 3y)^2 please tell me the wander ✌️