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Papessa [141]
3 years ago
5

Did i do this correct and i need help for the last question urgent

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0

Answer:

Correct so far.

The median score must be between positions 32 and 33 on the table.

The median score is 72.

Step-by-step explanation:

Correct so far.

The median score must be between positions 32 and 33 on the table.

The median score is 72.

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Simplify: x^d • x ^18
natta225 [31]

Answer:

x^(d+18)

Step-by-step explanation:

using the law of indices

you must add the powers

5 0
3 years ago
Read 2 more answers
What is the area of the shape
Radda [10]

Answer:

A= 18

Step-by-step explanation:

To find the height, find the blocks inside the shape that is completely attached (they have to be in a straight vertical line).  In this case, you can see that three vertical blocks in the middle of the shape is completely attached.  That means your height is 3.

To find the width, look at the how many horizontal boxes make up the top.  6 block inside the shape corispond with 6 blocks on top of the shape, so the width is six.

Multiply 6 by 3 to get 18.

7 0
3 years ago
It takes a day to build 2/3 of a model airplane gow many model airplanes can be built in 6 days​
Sedaia [141]

Answer:

4 airplanes

Step-by-step explanation:

1 = 2/3

6 = x

cross multiply

x = 6 × 2/3

therefore x = 4

5 0
2 years ago
Read 2 more answers
2. Solve the equation using the quadratic<br> formula.<br> -4x2 + 40x + 16 = 0<br> Page 1 of 2
kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

<em><u>Solution:</u></em>

Given equation is:

-4x^2 + 40x + 16 = 0

To find: solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16

<u><em>Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,</em></u>

\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0
3 years ago
Identify the initial amount a and the rate of decay r (as a percent) of the exponential function g(t) = 240(0.75)^t Evaluate the
Xelga [282]

A=240Answer:

Step-by-step explanation:

6 0
3 years ago
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