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3 years ago

What is the slope of a line that that contains the points (-5, -4) and (-1, -2)

Mathematics

1 answer:

9966 [12]3 years ago

7 0

Answer:

the answer is m=1/2

Step-by-step explanation:

if my answer right or wrong tell me and plz a like and rate. THANK YOU

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What is the domain and range of the relation shown?

Helga [31]

Answer:

{-4 ≤ x ≤ 4}

{-4 ≤ y ≤ 4}

Step-by-step explanation:

We’ll domain is the amount of x values,

Range is the amount of y values

_______________________________

Domain:

Starts from -4 to 4

{-4 ≤ x ≤ 4}

I made the sign less than or equal to because the circle lines are solid.

Range:

This starts from -4 to 4 also.

{-4 ≤ y ≤ 4}

Thus,

answer choices A. is correct

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Need help on these !! 13 and 14! Please!!

katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.

Step-by-step explanation: 

As the general sine function is given by

$y=asin(bx+c)+d$ .......[A]

amplitude = a
period = 2π ÷ b
Phase shift = -c ÷ b
Vertical shift = d

As in the question,

amplitude = a = 4
period = 4π
phase shift = -4π/3
Vertical shift = d = -2

period = 2π ÷ b

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b

c = b × 4π/3

c = 1/2 × 4π/3

c = 4π/6

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

$y=asin(bx+c)+d$

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2

Note: The graph is also shown in attached diagram.

Question # 14

Answer:

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

Step-by-step explanation: 

As the general cotangent function is given by

$y=acot(bx+c)+d$ .......[A]

amplitude = a
period = π ÷ b
Phase shift = -c ÷ b
Vertical shift = d

As in the question,

period = π
phase shift = -π/3
Vertical shift = d = 2

period = π ÷ b

b = π/period

b = π/π ∵ period = 4π

b = 1

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b

c = b × π/3

c = 1 × π/3

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and c = π/3 in Equation [A] would bring us the required equation for the given function.

$y=acot(bx+c)+d$

y = cot(x+π/3)+2

Note: The graph is also shown in attached diagram.

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0

3 years ago

Determine the initial height of the ball and the time interval before the ball hits the ground. initial height = 0; hits the gro

Anestetic [448]

Answer:

Answer: B) initial height = 150; hits the ground between 5 and 6 seconds

8 0

3 years ago

Read 2 more answers

Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. Se

son4ous [18]

Answer:

The question is incomplete, the complete question is "Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. See Example 9. $log_{4}7$ .

$log_{4}7=1.404\\$

Step-by-step explanation:

From the general properties or laws of logarithm, we have the

$log_{a}b=\frac{logb}{loga} \\$

where both log are now express in the natural logarithm base.

i.e $log_{a}b=\frac{lnb}{lna}\\$

hence we can express our $log_{4}7=\frac{ln7}{ln4} \\$ .

the value of ln7 is 1.9459 and ln4 is 1.3863

Hence $log_{4}7=\frac{ln7}{ln4}=\frac{1.9459}{1.3863}\\$ .

$log_{4}7=1.404\\$

6 0

3 years ago

Here are the boiling points elements in degrees Celsius

ladessa [460]

Answer:

Chlorine, Krypton, Argon, Fluorine, Hydrogen

Step-by-step explanation:

Look at the numbers and sort them from least to greatest. It could be the opposite answer to since the larger the negative number the smaller the value.

8 0

3 years ago

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