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3 years ago

To solve for the missing length, which operation should you perform?

Mathematics

2 answers:

Marysya12 [62]3 years ago

7 0

Answer:

Pythagorean theorem

Step-by-step explanation:

You should use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

9^2+ 12^2 = ?^2

81 +144 = ?^2

225 = ?^2

Take the square root of each side

sqrt(225) = sqrt(?^2)

15 =?

Radda [10]3 years ago

4 0

Answer:

? = 15 yards

Step-by-step explanation:

h² + b² = ?²

9² + 12² = ?²

81 + 144

225

√225 = 15

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Can someone help me…

aleksandr82 [10.1K]

Answer:

378$

Step-by-step explanation:

since u got 700ft^2 you would multiply 700 with 0.54 and get 378$

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2 years ago

Simplify -24/(-3)X(-4)

beks73 [17]

Answer:

- 2

Step-by-step explanation:

$\frac{-24}{(-3)(-4)}$ = $\frac{-24}{12}$ = - 2

5 0

3 years ago

9 * 6 * 10 / the power of 3

andreyandreev [35.5K]

Answer:

54,000

Step-by-step explanation:

10^3=1000

1000*6=6000

6000*9=54000

4 0

3 years ago

A rope is 66 feet long. It is cut into two pieces such that one piece is half the length of the other. What is the length of the

Shtirlitz [24]

Assume the longer piece is x feet long,

Then the other piece is 0.5x feet long

In total: x + 0.5x = 66 -> x = 44

So the longer piece is 44 feet, shorter piece is 22 feet

7 0

4 years ago

Read 2 more answers

The equation of a circle is x2 + y2 + Cx + Dy + E = 0. If the radius of the circle is decreased without changing the coordinates

tatyana61 [14]

Answer:

There will be no change in C and D but E must increase.

Step-by-step explanation:

We are given a equation of circle as:

$x^2+y^2+Cx+Dy+E = 0$

it could also be represented in general form of equation of circle as:

$(x+\dfrac{C}{2})^2+(y+\dfrac{D}{2})^2=\dfrac{C^2}{4}+\dfrac{D^2}{4}-E$

( since we add both the side of the equality by $\dfrac{C^2}{4}$ and $\dfrac{D^2}{4}$ )

Hence, on comparing the equation with general form of the equation:

$(x-g)^2+(y-h)^2=r^2$

The center of circle is (g,h) and radius is r.

Here we have the center as:

$(\dfrac{-C}{2},\dfrac{-D}{2})$

and radius is given aS:

$r=\sqrt{\dfrac{C^2}{4}+\dfrac{D^2}{4}-E}\\\\r=\sqrt{\dfrac{C^2+D^2-4E}{4}$

$r=\dfrac{\sqrt{C^2+D^2-4E}}{2}$

As there is no change in the center hence the value of $\dfrac{-C}{2}$ and $\dfrac{-D}{2}$ remains unchanged i.e. the value of C and D remains unchanged.

Now we are given that the radius of the circle is decreased.

that means the change in radius is due to the change in E.

Hence for the quantity $r=\dfrac{\sqrt{C^2+D^2-4E}}{2}\\$ to decrease E must increase so that the total quantity decreases.

Hence there will be no change in C and D but E must increase in order to decrease the radius of circle.

6 0

3 years ago

Read 2 more answers