Speed of rock before impact is 50 m/s
Given that;
Time taken by rock from bridge = 5 seconds
Find:
Speed of rock before impact
Computation:
Initial velocity = 0 m/s
Using first equation of motion
v = u + gt
v = 0 + (10)(5)
v = (10)(5)
v = 50 m/s
Final velocity = 50 m/s
Speed of rock before impact = 50 m/s
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Answer:
Step-by-step explanation:
According to the rules f(x) --> f'(x + a) is a horizontal shift right by a factor of -a, and f(x) --> f'(x) + a is a horizontal shift up by a factor of a, you can deduce that because x becomes x + 6, and |x| becomes |x| - 8, the translations are as shown above.
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