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atroni [7]
3 years ago
12

How do you write 345,000,000,000 in scientific notation

Mathematics
1 answer:
Tasya [4]3 years ago
8 0

Answer:

3.45 \times  {10}^{11}

Step-by-step Explanation:

345,000,000,000 = 3.45 \times  {10}^{11}  \\

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latisha has 7 boxes with 21 shells in each box. she has 6 bags with 17 shells in each bag. she uses 18 shells to make a design.
Neporo4naja [7]

Answer:

231

Step-by-step explanation:

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What is the sum of the series infinity e n-1 -7(3/8)^n?
soldier1979 [14.2K]

Let

S_N = \displaystyle \sum_{n=1}^N -7 \left(\frac38\right)^n = -7\left(\dfrac38 + \dfrac{3^2}{8^2} + \dfrac{3^3}{8^3} + \cdots + \dfrac{3^N}{8^N}\right)

Then

\dfrac38 S_N = -7\left(\dfrac{3^2}{8^2} + \dfrac{3^3}{8^3} + \dfrac{3^4}{8^4} + \cdots + \dfrac{3^{N+1}}{8^{N+1}}\right)

S_N - \dfrac38 S_N = -7 \left(\dfrac38 - \dfrac{3^{N+1}}{8^{N+1}}\right)

\dfrac58 S_N = -\dfrac{21}8 \left(1 - \left(\dfrac38\right)^N\right)

S_N = -\dfrac{21}5 \left(1 - \left(\dfrac38\right)^N\right)

As N\to\infty, the exponential term will converge to zero, so the infinite sum converges to

\displaystyle \sum_{n=1}^\infty -7 \left(\frac38\right)^n = \lim_{n\to\infty} S_N = \boxed{-\dfrac{21}5}

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2 years ago
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