Answer:
Step-by-step explanation:
![[(6^{2}+8^{2})^{\frac{1}{2}}]^{3} = [(36+64)^{\frac{1}{2}}]^{3}\\\\= [(100)^{\frac{1}{2}}]^{3}\\\\= 10^{3}\\\\= 1000](https://tex.z-dn.net/?f=%5B%286%5E%7B2%7D%2B8%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D%5E%7B3%7D%20%3D%20%5B%2836%2B64%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D%5E%7B3%7D%5C%5C%5C%5C%3D%20%5B%28100%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D%5E%7B3%7D%5C%5C%5C%5C%3D%2010%5E%7B3%7D%5C%5C%5C%5C%3D%201000)
Answer:x+21
Step-by-step explanation:
Answer:
The answer is 2:36
Step-by-step explanation:
The answer is 2:36 because 1:43 plus 56 minutes later would be 2:36
Answer:
They both talk for a different amount of time
Answer:
5 km.
Step-by-step explanation:
We have to calculate the distance if we apply the speed formula that would be the distance in a given time:
v = d / t
therefore, if we solve for distance it would be:
d = v * t
Now the speed is 6 km / h but the time must be calculated, it leaves at 9:15 and returns at 10:05, that is, there is no exact time but 50 minutes, one hour equals 60 minutes, therefore:
50 min * 1 h / 60 min = 0.833 h, that is, the child took 0.833 hours to get to school, now if we replace:
d = 6 * 0.8333
d = 5
In other words, the distance between the school and the house is 5 km.
