Solve the system of equations. y = x ^ 2

Silvie states that the sum of a rational number and an irrational number is sometimes rational and sometimes irrational. Which s

RideAnS [48]

Answer:

A) Silvie is incorrect; the sum of a rational number and an irrational number is always irrational

Step-by-step explanation:

The concept of adding rational and irrational numbers states that the result will always be irrational.

Take for instance the addition of 4.5 and 3.142857

4.5 is a rational number because it can easily be expressed in fractions while 3.142857 is irrational because it can't be expressed as a simple fraction.

The addition of these two numbers gives 7.642857

7.642857 is an irrational number.

Similarly, any sum of two numbers (rational and irrational) will always result in irrational number.

Hence, Silvie is incorrect.

4 0

3 years ago

An office supply company is shipping a case of

SSSSS [86.1K]

Pencils and easers hope ya how

3 0

2 years ago

What is the answer to 2 2/7 -8/7 can you show me how it done and show me the answer

GaryK [48]

You make 2 2/7 an improper fraction (16/7) and then you subtract 8/7 from 16/7 and you get 1 1/7 (or 8/7) as your final answer

7 0

4 years ago

Mr. cerna has 2/5 of a bag of candy and he is going to share it with 3 other people. How much candy will each person get.

goldenfox [79]

Answer:

2/15

Step-by-step explanation:

2/5 ÷ 3

2/5 x 1/3

(the imaginary 1 gets swapped with the numerator 3 ^)

2 x 1 / 5 x 3

= 2/15

8 0

4 years ago

Use the Normal model N(1133,78) for the weights of steers.

Rudiy27

Answer:

Step-by-step explanation:

Let $X\sim N(1133, 78)$ .

Here, the mean is 1133 and standard deviation is 78.

Since we don't have the table for N(1133, 78), so we use the standard table for N(0,1),

a)

All we have to do is find, within the table the specific percentile.

now to find (42nd percentile) 0.42 in the normal table N(0,1) and extract the number on the row and column.

$P(X\leq x)=0.42$

Using: $Z=\frac{X-\mu}{\sigma}$ where $\mu$ is the mean and $\sigma$ is the standard deviation.

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.42$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.42$

Now, using Standard Normal table to find the value of z- score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z.

i.e, $z= -0.20$

Now, putting this value in $z=\frac{x-1133}{78}$ , to find x;

$\frac{x-1133}{78}=-0.20$

On Simplify, we get;

$x=1,117.4$ pounds

b)

Similarly, find the weight for 91st percentile.

Follow the same steps that we have done in part (a),

$P(X\leq x)=0.91$ or

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.91$

⇒ $P(Z \leq \frac{x-1133}{78})=0.91$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.91$

Now, use normal table value to find the z-score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z

we have, z= 1.34

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=1.34$

On simplify, we get

x= 1,237.52 pounds

c)

the interquartile range (IQR)=3rd Quartile - 1st quartile

First find the 1st quartile:

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.25$

⇒ $P(Z \leq \frac{x-1133}{78})=0.25$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.25$

Now, we use normal table to find that z=-0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=-0.675$

On simplify, we get

x= 1,080.35 pounds

Similarly, for third quartile

By symmetry z=0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=0.675$

On simplify, we get

x= 1,185.65 pounds

then, IQR = 1185.65 -1080.35=105.3 pounds

7 0

4 years ago

Solve the system of equations. y = x ^ 2 - 3x + 6 y = 2x + 6