Answer:
<em>(1, 7) </em>
Step-by-step explanation:
y = 3x + 4
y = 6x + 1
6x + 1 = 3x + 4 ⇒ x = 1
y = 3(1) + 4 = 7
<em>(1, 7)</em>
He only made $10. Considering the horse was sold for $90.
Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
Answer:
y = -4x - 1
Step-by-step explanation:
The following data show the prices of different types of outfits at a store: $2, $2, $28, $26, $25, $27, $25, $27, $26, $28, $30
wlad13 [49]
Answer:
The box plot will have its left tail longer than the right tail becuase a few exceptionally low prices make the distribution skewed to the left.
Step-by-step explanation:
As seen in the attached file, the box plot has its left tail longer than the right tail because of the exceptionally low prices that is :$2
Firstly arranging the data in increasing order:
$2,$2,$25,$25,$26,$26,$27,$27,$28,$28,$30
Median of the data = 26 (since there are odd numbers)
Lower quartile (Q1) = 25
Upper quartile (Q2) = 26
By plotting the box plot we conclude that the left tail is longer than the right tail.
