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andrey2020 [161]
3 years ago
10

Solve the equation using the distributive property and properties of equality. Negative 5 (a + 3) = negative 55 14 -8 8 -14

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer:

11

Step-by-step explanation:

55 divide 5 = 11

11 + 3 = 15

5 × 11 = 55

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What is equivalent to 6/25. A.0.20 B.0.22 C. 0.24 D. None
padilas [110]

Answer:

C. .024

Step-by-step explanation:

You multiply 25 by 4 to get 100 and then you multiply 6 by 4 to get twenty four. After that you divide both numbers by one hundred and you get C

5 0
3 years ago
Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form.
ololo11 [35]

Answer: Perimeter = 22*sqrt(2)

Area = 60.5 inches

Step-by-step explanation:

Simple a  square has 4 equal sides.

It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

7 0
3 years ago
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What is 1/5 ÷ 5<br> someone pls help me
Elena-2011 [213]

Answer: 1/25 or 0.04

Step-by-step explanation:

1/5 divided by 5 for the whole number you have to turn it to a fraction so you would do 5/1

THEN: it becomes 1/5 divided by 5/1 but you have to do the inverse so the inverse of division is multiplying and you will cross multiply so 5*5= 25 and 1*1=1 therefor the final answer is 1/25

5 0
2 years ago
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Tell whether the triangle with the given side lengths is a right triangle.
kramer

Answer:

no

Step-by-step explanation:

so in order for it to be a right triangle this would have to be true:

a^2 + b^2 = c^2

since c represents the hypoteneuse, it will be the longest side. so:

60^2 + 63^2 = 88^2

3600 + 3969 = 7744

7569 = 7744

since that statement is not true, the answer is no.

it is not a right triangle  

the square root of 7569 is 87, so the triple would have to be : {60,63,87}

4 0
3 years ago
3 Prove that<br>cos130°+cos 110+ cos10=0​
Evgesh-ka [11]

We know, cos A + cos B = 2cos(C+D)/2 × cos(C - D)/2

So,

cos 130 + cos 110 + cos 10

cos 130 + 2cos (110+10)/2 × cos( 110-10)/2

cos 130 + 2cos 60 × cos 50

cos ( 180 - 50 ) + 2cos60 cos 50

We know, cos ( 180 - A ) = -cos A

2cos 60 cos 50 - cos 50

Also, cos 60 = 0.5

2×0.5 cos 50 - cos50

cos 50 - cos 50

0  = RHS.

Hence proved

5 0
3 years ago
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