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prisoha [69]
3 years ago
9

HEEEEEEEEEEEEELLLLLLLLLLPPPPPPPPPP

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0
The answer is B, 5/6, because when you multiply 4 by 5 it is 20, and when you multiply 5 by 6, you get 30, so 20/30. And, 20/30=2/3. I hope I answered your question!
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If f(x) = 5x + 40, what is f(x) when x = -5?<br> 0-8<br> 0.7<br> O 15
Over [174]

Answer:

15

Step-by-step explanation:

f(x) = 5x + 40

…………………………

when x = -5

f(-5) = 5(-5) + 40

      = -25 + 40

      = 40 - 25

      = 15

4 0
2 years ago
A school is having a canned food drive. Each class is challenged to collect 220 cans. If there are x classes in the school, whic
lara31 [8.8K]

Answer:

B)

Step-by-step explanation:

no. of Classes = x

cans = 220

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Answer:

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2 years ago
What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x
konstantin123 [22]

Answer:

f(x)=x^{3}-3x^{2} +4x-2

Step-by-step explanation:

we know that

The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial

In this problem we have that

The polynomial has roots 1 and (1+i)

so

by the conjugate root theorem

(1-i) is also a root of the polynomial

therefore

The lowest degree of the polynomial is 3

so

f(x)=a(x-1)(x-(1+i))(x-(1-i))

Remember that

The leading coefficient is 1

so

a=1

f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2

5 0
3 years ago
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Two rays that intersect at their initial point.
dolphi86 [110]
That is called an angle.
4 0
3 years ago
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