All categories

3 years ago

HEEEEEEEEEEEEELLLLLLLLLLPPPPPPPPPP

Mathematics

1 answer:

Vika [28.1K]3 years ago

4 0

The answer is B, 5/6, because when you multiply 4 by 5 it is 20, and when you multiply 5 by 6, you get 30, so 20/30. And, 20/30=2/3. I hope I answered your question!

You might be interested in

If f(x) = 5x + 40, what is f(x) when x = -5? 0-8 0.7 O 15

Over [174]

Answer:

Step-by-step explanation:

f(x) = 5x + 40

…………………………

when x = -5

f(-5) = 5(-5) + 40

= -25 + 40

= 40 - 25

= 15

4 0

2 years ago

A school is having a canned food drive. Each class is challenged to collect 220 cans. If there are x classes in the school, whic

lara31 [8.8K]

Answer:

Step-by-step explanation:

no. of Classes = x

cans = 220

220×x = 220x

no.of classes × cans = total number of cans

5 0

2 years ago

Read 2 more answers

HELPPPP PLSSSSSSSSSSSSSSSSSSSS

forsale [732]

Answer:

.um g o o g l e look it u p I do that.

5 0

3 years ago

What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x

konstantin123 [22]

Answer:

$f(x)=x^{3}-3x^{2} +4x-2$

Step-by-step explanation:

we know that

The conjugate root theorem states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial

In this problem we have that

The polynomial has roots 1 and (1+i)

by the conjugate root theorem

(1-i) is also a root of the polynomial

therefore

The lowest degree of the polynomial is 3

$f(x)=a(x-1)(x-(1+i))(x-(1-i))$

Remember that

The leading coefficient is 1

a=1

$f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2$

5 0

3 years ago

Read 2 more answers

Two rays that intersect at their initial point.

dolphi86 [110]

That is called an angle.

4 0

3 years ago

Read 2 more answers