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Anestetic [448]
3 years ago
13

Convert the algebraic expression below to C++ statement Do not use the pow function. Ans = 5x^2 + 15k + y^-2

Computers and Technology
1 answer:
kramer3 years ago
7 0

Answer:

The C++ statement for the given algebraic expression 5x^2 + 15k + y^-2 is ( ( 5 * ( x * x ) ) + ( 15 * k ) + ( 1 / ( y * y ) ).

Explanation:

To convert the given algebraic expression 5x^2 + 15k + y^-2 into the C++ statement without using the pow function is:

In the given algebraic expression, there are three expressions combined using the + operator.

The first algebraic expression is 5x^2.

Here, x has a power of 2, and 5 is multiplied by the result of x^2. x having the power of 2 means x is multiplied itself twice. The C++ statement for this algebraic expression is (5 * ( x * x)).

The second algebraic expression is 15k.

Here, 15 is multiplied by k. The C++ statement for this algebraic expression is (15 * k).

The third algebraic expression is y^-2.

Here, x has a power of -2. it means 1/y^{2}.  The C++ statement for this algebraic expression is (1/ (y * y).

The combination of all the three C++ statement is (5 * ( x * x)) + (15 * k) + (1/ (y * y).

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3 0
3 years ago
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Using truth table, prove that:<br><br> (A + B). C = (A . C)+ (B .C) ?
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Answer:

The image of truth table is attached.

Explanation:

In the truth table there is a separate table for the expression (A+B).C and for the expression (A.C)+(B.C) you can see in the truth table that the columns of (A+B).C is having same values as the (A.C)+(B.C).Hence we can conclude that (A+B).C is equal to (A.C)+(B.C).

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For a new version of processor, suppose the capacitive load remains, how much more energy will the processor consume if we incre
erastovalidia [21]

Answer:

The answer is below

Explanation:

The amount of power dissipated by a processor is given by the formula:

P = fCV²

Where f = clock rate, C = capacitance and V = Voltage

For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:

P(old) = fCV²

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