48 is the answer of your mathematics question on this site/app.
Clearly, |S| = 50.
Count the multiples of 2 between 1 and 50:
⌊50/2⌋ = ⌊25⌋ = 25
(where ⌊x⌋ denotes the "floor of x", or the largest integer that is smaller than or equal to x; in other words, round <u>down</u> to the nearest integer)
Count the multiples of 3 between 1 and 50:
⌊50/3⌋ ≈ ⌊16.667⌋ = 16
Since LCM(2, 3) = 6, the sets of multiples of 2 and multiples of 3 have some overlap. Count the multiples of 6 between 1 and 50:
⌊50/6⌋ ≈ ⌊8.333⌋ = 8
Then by the inclusion/exclusion principle, we remove from S
25 + 16 - 8 = 33
elements, so that the new set S contains 50 - 33 = 17 elements.
Answer:
2.3
Step-by-step explanation:
move the decimal to the right two times
Answer: x = - 16
y = - 11
Step-by-step explanation:
The given system of linear equations is expressed as
2x - 3y = 1- - - - - - - - - - - - -1
x - 2y = 6 - - - - - - - - - - - -2
We would eliminate x by multiplying equation 1 by 1 and equation 2 by 2. It becomes
2x - 3y = 1- - - - - - - - - - -3
2x - 4y = 12- - - - - - - - - - - -4
Subtracting equation 4 from equation 3, it becomes
y = - 11
Substituting y = - 11 into equation 2, it becomes
x - 2 × - 11 = 6
x + 22 = 6
Subtracting 22 from the left hand side and the right hand side of the equation, it becomes
x + 22 - 22 = 6 - 22
x = - 16
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