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3 years ago

Can you guys Divide and check using Multiplication for these 2 Problems? 1st: 326 Divided by 53. And 192 Divided by 38

1 answer:

7 0

Ya if you divide 326 by 53 and if you multiply it then you have to add the reminder to it. Divide 192 by 38 and you multiply it and add the reminder if there is one.

HOPED I HELPED YOU!!!!!!!!!!!

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PLEASE ANSWER ASAP!!!! If b = 3, then b -2 is equivalent to _____? 9 -9 -6 1/9

kirill115 [55]

$3^{-2}$ is basically $\frac{1}{3^{2} }$ , which is $\frac{1}{9}$ .
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Hope this helps!
==jding713==

4 0

3 years ago

Donut $2.50 Cupcake $4.25 Ice cream $3.80 I need help finding the equation

kati45 [8]

The answer is 10.55 l hope this helps

5 0

3 years ago

Give the numerical value of the parameter p in the following binomial distribution scenarioA softball pitcher has a 0.721 probab

Igoryamba

Answer:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

For this case our random variable is given by:

$X \sim Binom(n = 19, p = 0.721)$

For this case we want this probability:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

3 0

4 years ago

1/2(x + 5)2 + 2 = 42.5

Monica [59]

Answer:

x=35.5

Step-by-step explanation:

reduce numbers

remove parentheses

add the numbers

move constant to the right

subtract numbers

7 0

3 years ago

Read 2 more answers

A function follows the rule y = -75 - 5 x . When the function's output is 25, the equation is 25 = -75 - 5 x .

zhenek [66]

Answer:

same here idek tbh

Step-by-step explanation:

.......

3 0

3 years ago