Let 1993 = time 0 = 0.
Let 1999 = time 6 = 6
Let 2012 = time 19 = 19
So, a = 171 (million). First solve for k.
176 = 171 e^k6
176/171 = e^(k*6)
ln (176/171) = 6k
k = 1/6 ln (176/171)
So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)
Hope this helped!
Answer: <em>ok so if 60% is under 25 then we can assume 40% is over 25, and then do 40% of 450,000, which is 180,000 .</em>
<em>so we can say that 180,000 people in the town are over 25 years old</em>
Answer: Your answer is 2) SAS
Step-by-step explanation: Yes, there are congruent.
Answer:
g(x)= 5
Step-by-step explanation:
Evaluate F(X) for 2
3(2)-1
6-1
5
And that is the value of G(X)
X is less than or equal to -1.5
