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2 years ago

Mark is thinking of two numbers

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

7 0

9514 1404 393

Answer:

-2, 3

Step-by-step explanation:

For the product to be negative, exactly one of the two numbers must be negative. For the sum to be positive, the positive number must be larger than the absolute value of the negative number.

One such pair of numbers is -2 and 3.

Their product is -6; their sum is +1.

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Find the measure of the exterior angle 1. with one angle is 50 degrees and 28 degrees

OLga [1]

Answer:

D. 78°

Step-by-step explanation:

50°+28°= 78°

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3 0

2 years ago

What is the equation of the line that passes through the point (−3,−11) and is parallel to the line with the equation y=2x−4

tester [92]

parallel means same slope. m = 2

y - y₁ = m(x - x₁)

y - (-11)= 2(x - (-3))

y + 11 = 2(x + 3)

y + 11 = 2x + 6

-11 -11

y = 2x - 5

Answer: A

5 0

3 years ago

Could you guys plesssse help me with 3 and 4

SOVA2 [1]

Number four is B. 28.

7 0

3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

2 years ago

Read 2 more answers

Pairs that satisfy function y=2x+1

evablogger [386]

Test a pair from each table by substituting their values into the given equation and solving.

A) y = 2x + 1 .......... 2 = 2(0) + 1 .......... 2 ≠ 1

B) y = 2x + 1 .......... 1 = 2(0) + 1 .......... 1 = 1

C) y = 2x + 1 .......... -1 = 2(0) + 1 .......... -1 ≠ 1

D) y = 2x + 1 .......... -2 = 2(0) + 1 .......... -2 ≠ 1

The only pair that satisfied the equation was from answer choice B. Therefore, B is the correct answer.

8 0

2 years ago