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3 years ago

Mark is thinking of two numbers

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

7 0

9514 1404 393

Answer:

-2, 3

Step-by-step explanation:

For the product to be negative, exactly one of the two numbers must be negative. For the sum to be positive, the positive number must be larger than the absolute value of the negative number.

One such pair of numbers is -2 and 3.

Their product is -6; their sum is +1.

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Solve P=2(l+w) for l

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3 years ago

Suppose we have an urn containing 9 marbles. Two are red, three are green, and four are blue. We randomly select 5 marbles from

Aleonysh [2.5K]

Answer:

probability of selecting 3 green marbles, 1 red marble, and 1 blue marbles

$P(E) =\frac{8}{126} = 0.0634$

Step-by-step explanation:

Given data urn containing '9' marbles

given red marbles = 2

green marbles =3

blue marbles = 4

Five marbles can be selected at a time from '9' marbles in $9_{C_{5} }$ ways

by using formula $n_{C_{r} }=\frac{n!}{(n-r)!r!}$

$9_{C_{5} }=\frac{9!}{(9-5)!5!} = \frac{9X8X7X6X5!}{4!5!}$

After simplification , we get $9_{C_{5} } = 126$

total number of ways n(S) = 126

The probability of selecting '3' green marbles ,one red marble and one blue marble with replacement.

let ' E' be the event of selecting '3' green marbles ,one red marble and one blue marble with replacement.

n(E) = $3_{C_{3} } X2_{C_{1} }X 4_{C_{1} }$ ways

The required probability $P(E) = \frac{n(E)}{n(S)}$

$p(E) = \frac{3_{C_{3} } X2_{C_{1} }X 4_{C_{1} }}{9_{C_{5} } }$

on simplification , we get

$P(E) = \frac{1X2X4}{126} =\frac{8}{126}$

$P(E) =\frac{8}{126} = 0.0634$

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4 years ago

Express the following rational number as decimals 1/ 16

Marizza181 [45]

Answer:

Step-by-step explanation:

The answer is 0.0625

Hope this helps

plz mark as brainliest!!!

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3 years ago