SOMEONE HELP ME PLEASE

Mathematics

2 answers:

Ksivusya [100]3 years ago

7 0

Ξηφηφξδξδξξδδηδξδξδηηδδνφηφηφηφβηφβφηφηφηγφβδηψηδηφξ

marin [14]3 years ago

5 0

Answer:

Step-by-step explanation:

Direct variation problems can easily be solved with proportions, namely:

$\frac{x}{y} :\frac{2}{5}=\frac{4}{y}$ and cross multiply to get

2y = 20 so

y = 10

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You have 1 case of soap bars and there are 150 bars in a case. You use 300 bars of soap per day. How many cases do you need to o

diamong [38]

Answer:
14 cases

Explanation:
First, we will need to find the number of cases needed per day:
We know that one case includes 150 bars and that the daily consumption is 300 bars. To know the number of cases needed daily, we will use cross multiplication as follows:
1 case .............> 150 bars
?? cases .........> 300 bars
number of cases needed daily = $\frac{300*1}{150}$ 
number of cases needed daily = 2 cases

Then, we will get the number of cases needed weekly (7 days):
We know that 2 cases are needed daily. To know the number of cases needed weekly (7 days), we will simply use cross multiplication as follows:
1 day .............> 2 cases
7 days ...........> ?? cases
number of cases needed weekly = $\frac{7*2}{1}$ 
number of cases needed weekly = 14 cases

Hope this helps :)

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3 years ago

Movie tickets cost 9.25 each and a large order of popcorn costs 7.75. what is the total cost of 5 movie tickets and a large orde

aev [14]

9.25 x 5 + 7.75 = 54

8 0

3 years ago

Read 2 more answers

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill

abruzzese [7]

Answer:

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year

Step-by-step explanation:

Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

$V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}$