All categories

2 years ago

The reasons as well as the answer

Mathematics

2 answers:

Misha Larkins [42]2 years ago

5 0

Answer:

x=46° and y=67°

Step-by-step explanation:

triangle ACE is isosceles, meaning <A=<B=y

any triangle is add up to 180. <A+<B+<C=180

y+y+46=180

2y=180-46

2y=134

divide both sides by 2

y=134/2

y=67°

for angle x°

since AB is parallel to CD,hence

<AEC=<ECD

x=46°

Radda [10]2 years ago

4 0

Answer:

x = 46, y = 67

Step-by-step explanation:

x = ∠ AEC = 46 ( alternate angles )

Since Δ ACE is isosceles then the base angles are congruent, then

y = $\frac{180-46}{2}$ = $\frac{134}{2}$ = 67

You might be interested in

A season has 81 home games. If you

skelet666 [1.2K]

Answer:

972$

Step-by-step explanation:

8 0

2 years ago

0.08 and 0.4 as fractions in simplest form

IRISSAK [1]

0.08 equals 2/25
0.4 equals 2/5

6 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

2 years ago

Read 2 more answers

Question on image down below

denpristay [2]

Answer:

The temperature at sunrise was lower on the day in 2012 than on the day in 2013.

The difference between the 2012 and 2013 rates of temperature increase was 0.1 degrees per hour.

Both days had a constant rate of change in temperature per hour over the time periods shown.

Step-by-step explanation:

I don't know of that's right but . . .

5 0

2 years ago

Lorenzo wants to know how much it will cost to rent tables and chairs for an event. He investigates renting tables and chairs an

Savatey [412]

Answer:

C: 12x + 40

Step-by-step explanation:

We are told that the Cost to rent tables from Company A is;

f(x) = 4x + 25

Also, we are told that the Cost to rent tables from Company B is;

g(x) = 2(4x) + 15

Thus, total cost for Lorenzo to rent x number of tables and the chairs he needs is;

Total = f(x) + g(x)

Total = 4x + 25 + 2(4x) + 15

Total = 4x + 25 + 8x + 15

Total = 12x + 40

5 0

2 years ago