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lapo4ka [179]
3 years ago
14

What is the approximate area of the figure below?

Mathematics
2 answers:
aalyn [17]3 years ago
7 0
<h2>YOUR ANSWER IS IN THE ATTACHMENT PLZZ REFER TO THE ATTACHMENT </h2><h2>MARK ME BRAINLIEST AND FOLLOW ME </h2>

dem82 [27]3 years ago
5 0
48 cm squared is your answer!
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Is it B, am I right, please answer fast.
yKpoI14uk [10]

Answer: C

Step-by-step explanation:

I’m pretty sure it’s c because x isn’t less than -2. It goes forever in the directions of positive and negative infinity

8 0
3 years ago
Read 2 more answers
A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random
Alenkasestr [34]

Answer:

a. Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

b. t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

c. p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2>0

Our notation on this case :

n_1 =78 represent the sample size for group 1

n_2 =21 represent the sample size for group 2

\bar X_1 =92.88 represent the sample mean for the group 1

\bar X_2 =86.90 represent the sample mean for the group 2

s_1=15.34 represent the sample standard deviation for group 1

s_2=8.99 represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom. If we replace the values given we have:

t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

Now we can calculate the degrees of freedom given by:

df=78+21-2=97

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

6 0
3 years ago
If a table seats 7, what is the least number of tables needed to seat 155 people
Fynjy0 [20]

23 is the minimum because 155 does not go into evenly and you have to have enough room for everybody, and make sure not to leave anybody out. 155 divided by 7 is 22.1428571429, you have to round it up to 23 so that everybody has a seat. Hope it helps!!

7 0
3 years ago
your order comes in for new protective eye wear. you order five and a half dozen. how many individual protective eye wear should
Serga [27]
 You should have received  33 pairs of protective eyewear

To Check This:
1 dozen = 12
1/2 dozen = 6
5 dozen = 60

12x5=60+6=66
66 / 2 = 33 because a pair equals 2
4 0
4 years ago
Please Help me on this question<br> hurrryyyyy!!!!!!!!!!!!!<br> PLZ<br> Brainliest​ Available
postnew [5]
Group 46 - 55, total 76

25 out of 76 are excellent
so
25/76 = 0.3289

answer
32.89%


8 0
3 years ago
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