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3 years ago

HELP please will give brainiest!! No robots please,

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

4 0

Answer:

Slope is -4/5

Y-intercept is -2

Step-by-step explanation:

use equation y=mx+b

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Write the log equation as an exponential equation. You do not need to solve for x.

jok3333 [9.3K]

Answer:

4 = $e^{3x + 1}$

Step-by-step explanation:

3 0

3 years ago

In order to solve for the variable in the equation 2 (x + 3) + 5 x = 3 (2 x minus 1), Jaleesa begins by applying the distributiv

avanturin [10]

Answer: 7 x + 6 = 6 x minus 3

Step-by-step explanation:

2 (x + 3) + 5 x = 3 (2 x minus 1)
Now you distribute.
2(x) + 2(3) = 2x+6
And 3(2x) minus 3(1) = 6x minus 3
2x+6+5x = 6x minus 3
Then combine like terms
2x +5x=7x and there are no other like terms on either side of the equation.
7x+6= 6x minus 3

8 0

3 years ago

Read 2 more answers

What polynomial can be factored to give (a + 4) ( a - 4) ?

iragen [17]

Answer:

(a+4)(a-4)=a²-4² ITS LIKE THIS BECAUSE ITS AN IDENTITY,

⇒a²-16

Even when we solve it by the regular method of solving polynomials we get a²-16 as answer as there and thats the proof for the identity.

(a+b)(a-b)=a(a-4)+4(a-4)

⇒a²-4a+4a-16

⇒a²-16[NOTE:-4a+4a=0]

Thus we can see that a²-16 is the answer we get when we try to solve it by regular polynomial solution tooo.

And a²-16 is the polynomial from which we get (a+4)(a-4)

8 0

3 years ago

Please help me find out what the question marks are

quester [9]

Question a

g(x) times $\sqrt{x-5}=\sqrt{x^2-5}$
divide both sides by √(x-5)
$g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}$
$g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}$
$g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$

question b
$g(x) \space\ times \space\ 1+\frac{1}{x}=x$
divide both sides by 1+1/x
$g(x)=\frac{x}{1+\frac{1}{x}}$
times by x/x
$g(x)=\frac{x^2}{x+1}$

question c
$\frac{1}{x} \space\ times \space\ f(x)=x$
times both sides by x
$f(x)=x^2$

question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
$|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})$
so f(x)=√x

a. $g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$
b. $g(x)=\frac{x^2}{x+1}$
c. $f(x)=x^2$
d. $f(x)=\sqrt{x}$

3 0

4 years ago

Read 2 more answers

B. lam greater than 310. My number

KonstantinChe [14]

Answer:

four hundred and forty two

3 0

3 years ago