Question

What is the equation in point slope form of a line that passes through the points (-8,2) and had a slope of 1/2

Answer 1

Answer:

$y-2=\dfrac{1}{2}(x+8)$

Step-by-step explanation:

It a line passes through the point $(x_1,y_1)$ with slope m, then the point slope form of the line is

$(y-y_1)=m(x-x_1)$      ....(i)

It is given that line passes through the point (-8,2) and had a slope of 1/2.

We neeed to find the  equation in point slope form of the line.

Substitute $x_1=-8,y_1=2\text{ and }m=\dfrac{1}{2}$ in equation (i).

$(y-(2))=\dfrac{1}{2}(x-(-8))$

$y-2=\dfrac{1}{2}(x+8)$

Therefore, the point slope form of the line is $y-2=\dfrac{1}{2}(x+8)$.

Answer 2

First you have to plug in your information into the formula- y=mx+b
So we know the y is 2, the slope (m) is 1/2, the x is 2 and we don't know the b. Do plug it in the formula and solve... you should get 2=1/2(2)+b you will end up with 1=b and the final answer is y=1/2x+1