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valentinak56 [21]
2 years ago
10

C. Tyler's brother earns $12 per hour. The store offers him a raise-a 5% increase per hour. After the

Mathematics
1 answer:
Valentin [98]2 years ago
6 0

Answer:

The answer is $12.60

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I think it would be nine
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2 years ago
Solve for x.<br> -1/5 (x - 4) = -2<br><br> Enter your answer in the box.<br><br> x = ________
Lena [83]

Answer: x=14

Step-by-step explanation:Simplify both sides of the equation(Distribute),Subtract 4/5 from both sides.Multiply both sides by 5/(-1).

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Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
  • The third choice \left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace
  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

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  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

8 0
3 years ago
In circle N, KL ≅ ML. What is the measure of ?
pentagon [3]
This is the concept of geometry, for us to get the value of JM we will requires to get the value of x first;
From the diagram we have been told that;
KL=ML
KL=7x+7
ML=8x-3
thus;
8x-3=7x+7
collecting the like terms we get;
8x-7x=7+3
x=10
But, JM=13x+2
substituting the value of x in JM we get:
JM=13(10)+2
JM=130+2
JM=132
The answer is 132°

3 0
3 years ago
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Choose the correct answer. &gt; &lt; = We can't compare them= fastbridge quiz amath
Luba_88 [7]

Answer:

show the picture

Step-by-step explanation:

8 0
2 years ago
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