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Sphinxa [80]
3 years ago
10

Please help me with Part B I will give you points and thanks! Thank you

Mathematics
2 answers:
Mumz [18]3 years ago
6 0
2.12=2.120 that is the answer
Papessa [141]3 years ago
4 0

2.120 kg and 2.12 kg are inherently the same, the zero on 2.120 is actually slightly unnecessary (unless a function asks for a certain tenth's or thousands place to be defined). This problem asks you to write an equation representing this information, I believe the easiest way to do this would be

2.120 kg = 2.12 kg

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Elenna [48]

Answer:

Step-by-step explanation:

6 0
3 years ago
Here is my question: 2n + 4 = 4n + 1 - 2n
kogti [31]

Answer:

0 solutions

Step-by-step explanation:

2n + 4 = 4n + 1 - 2n

                        ↑

first combine like terms (right side)

2n + 4 = 2n + 1

but this part you can tell that there's 0 solutions, because both sides have 2n/ same variable with same number.

3 0
4 years ago
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I need somebody’s help
lisabon 2012 [21]

Answer:

x= 40

so

3x-5= 115

2x-15= 65

Step-by-step explanation:

C is the correct answer. I see that you put a mark on that choice so you are right if you thought that. I hope this helps!

6 0
3 years ago
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Let f be the function given by f(x)=3xsinx. What is the average value of f on the closed interval 1≤x≤7 ?
Hoochie [10]

Answer:

-2.92178

Step-by-step explanation:

Given the function f(x)=3x\ sin x

The average,A is calculated using the formula;

A=\frac{1}{b-a}\int\limits^a_b F(x)\, dx \\\\A=\frac{1}{7-1}\int\limits^7_1 3x \ Sin \ x\, dx \\\\\\=\frac{3}{6}\int\limits^7_1 x \ Sin \ x\, dx \\\\\#Integration\  by\  parts, u=x, v \prime=sin(x)\\=0.5[-xcos(x)-\int-cos(x)dx]\limits^7_1\\\\=0.5[-xcos(x)-(-sin(x))]\limits^7_1\\\\=0.5[-xcos(x)+sin(x)]\limits^7_1\\\\=0.5[-6.82595--0.98240]\\\\=-2.92178

Hence, the average of the function is -2.92178

8 0
3 years ago
Volume=<br> Help me please thanks so much
Artemon [7]

Answer:

30.7

Step-by-step explanation:

It's 30.7 because 707/23

4 0
2 years ago
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