Answer:
Step-by-step explanation:
It must be a trapezoid because a trapezoid has at least one set of parallel sides. Sides of equal length don't mean anything really unless we know hose sides are parallel. I will say sometimes I hear trapezoids ONLY have two parallel sides, while the other two are not, while in other places as long as two are parallel it is a trapezoid. It looks like for this question it is using the definition that at least two parallel sides makes it a trapezoid.
it can be an isosceles trapezoid since it is a type of trapezoid, same with right trapezoid. Basically any special kind of trapezoid
parallelogram because it can have two pairs of parallel lines and have thos parallel sides be equal. So this also means it can be all kinds of parallelograms.
Do you have a list to choose from? because most I pull up don't include right trapezoid at least.
This leaves kite as the only kind of quadrilateral to look at yet, and it specifies no parallel sides. bt your shape need at least one set of them, so it cannot be a kite.
Answer:
Difference indicates subtraction: The difference of a number and 9 is (x−9) Twice the difference means 2(x−9) We know that the answer to this is 2 , so as an equation: 2(x−9)=2.
Step-by-step explanation:
:|
Answer:
(y + 7i)(y - 7i)
Step-by-step explanation:
It cannot be factored using real numbers, but consider
7i × - 7i
= -49i² and i² = - 1
= 49
The factoring as a difference of squares to obtain
y² + 49 = (y + 7i)(y - 7i)
so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).
![\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bf%28x%29%7D%7B0%7D%3D-%28x-3%29%28x%2B11%29%5Cimplies%200%3D%28x-3%29%28x%2B11%29%5Cimplies%20x%3D%20%5Cbegin%7Bcases%7D%203%5C%5C%20-11%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cboxed%7B-11%7D%5Cstackrel%7B%5Ctextit%7B%5Clarge%207%20units%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D-4%5Cstackrel%7B%5Ctextit%7B%5Clarge%207%20units%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%5Cboxed%7B3%7D)
so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?
![\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20f%28-4%29%3D-%28-4-3%29%28-4%2B11%29%5Cimplies%20f%28-4%29%3D7%287%29%5Cimplies%20f%28-4%29%3D49%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7Bvertex%7D%7B%28-4~~%2C~~49%29%7D~%5Chfill)

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