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ANTONII [103]
3 years ago
11

AB is tangent to circle O at B. Find the length of the radius r for AB = 5 and AO = 8.6. Round to the nearest tenth if necessary

. The diagram is not to scale.. . Answer. a.3.6. b.13. c.7. d.9.9.
Mathematics
2 answers:
diamong [38]3 years ago
5 0

The length of the radius r for AB = 5 and AO = 8.6 is 7. The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

OverLord2011 [107]3 years ago
4 0
The answer to this question is <span>c.7</span>
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Which property is illustrated by the equation below:<br> 6(5+1)=6(5)+6(1)
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Answer:

distribution property

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How can you find the sample space of two or more events?
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Just multiply the total number of outcomes with the expected.

Step-by-step explanation:

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3 years ago
A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo
defon

Answer:

a) The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

b) P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

c) P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

X \sim Unif (a= 10, b =12)

Part a

The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

Part b

For this case we want this probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

Part c

For this case we want this probability:

P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

3 0
4 years ago
Two similar pyramids have lateral areas 20ft2 and 45ft2. The volume of the smaller pyramid is 8ft3.
Artemon [7]
Let the ratio between 2 of them be a/b. The volume of the larger one is x (ft^3) 
<span>(a/b)^2 = 20/45 = 4/9 ---> a/b = 2/3 </span>
<span>(a/b)^3 = 8/x </span>
<span>8/x = (2/3)^3 = 8/27 ---> x = 27 (ft^3) </span>
5 0
3 years ago
Read 2 more answers
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