First find the slope, take derivative of both sides with respect to x.  
2y dy/dx=3x^2+6x
solve for dy/dx
dy/dx=[3x^2+6x]/2y
plug in given vales of (1,2(
dy/dx=9/4
now you have everything you need to plug into point slope form
y-2=(9/4)(x-1)
answer is y=(9/4)x+(1/4)
        
             
        
        
        
We performed the following operations:
![f(x)=\sqrt[3]{x}\mapsto g(x)=2\sqrt[3]{x}=2f(x)](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%5Cmapsto%20g%28x%29%3D2%5Csqrt%5B3%5D%7Bx%7D%3D2f%28x%29)
If you multiply the parent function by a constant, you get a vertical stretch if the constant is greater than 1, a vertical compression if the constant is between 0 and 1. In this case the constant is 2, so we have a vertical stretch.
![g(x)=2\sqrt[3]{x}\mapsto h(x)=-2\sqrt[3]{x}=-g(x)](https://tex.z-dn.net/?f=g%28x%29%3D2%5Csqrt%5B3%5D%7Bx%7D%5Cmapsto%20h%28x%29%3D-2%5Csqrt%5B3%5D%7Bx%7D%3D-g%28x%29)
If you change the sign of a function, you reflect its graph across the x axis.
![h(x)=-2\sqrt[3]{x}\mapsto m(x)=-2\sqrt[3]{x}-1=h(x)-1](https://tex.z-dn.net/?f=h%28x%29%3D-2%5Csqrt%5B3%5D%7Bx%7D%5Cmapsto%20m%28x%29%3D-2%5Csqrt%5B3%5D%7Bx%7D-1%3Dh%28x%29-1)
If you add a constant to a function, you translate its graph vertically. If the constant is positive, you translate upwards, otherwise you translate downwards. In this case, the constant is -1, so you translate 1 unit down.
 
        
             
        
        
        
Answer:
The correct answer is 2+2=4 
thanks 
 
        
             
        
        
        
I think D (sorry if I’m wrong)
        
             
        
        
        
Study it! Flash cards are a good idea!