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Tasya [4]
3 years ago
10

Help me! i need this answer

Mathematics
1 answer:
kirill115 [55]3 years ago
4 0

Answer:

x=15

Step-by-step explanation:

Please mark brainliest

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What is true about the solution of x^2/2x-6=9/6x-18?
Marizza181 [45]
\text{The domain:}\\2x-6\neq0\ \wedge\ 6x-18\neq0\\D:x\neq3\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{6x-18}\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{3(2x-6)}\\\\\dfrac{x^2}{2x-6}=\dfrac{3}{2x-6}\iff x^2=3\to x=\pm\sqrt3
Answer:
<span>x= +-√3 and they are actual solutions.</span>

6 0
4 years ago
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In analyzing data from over games in the National Football League, economist David Romer identified fourth-down situations in wh
mash [69]

Answer: Subtract 9 to equal to negative four

Step-by-step explanation:

6 0
3 years ago
What is the following product?
Zarrin [17]

Answer: A

Step-by-step explanation:

(\sqrt{12}+\sqrt{6})(\sqrt{6}-\sqrt{10})

(\sqrt{12}*\sqrt{6})-(\sqrt{12}* \sqrt{10})+(\sqrt{6}*\sqrt{6})-(\sqrt{6}*\sqrt{10})

(\sqrt{12*6})-(\sqrt{12*10})+(\sqrt{6*6})-(\sqrt{6*10})

Let's rewrite the numbers inside to see if we can take some out.

For example; 12 is 3 x 4 and 4 is 2^2 which means a 2 will come out of the root.

(\sqrt{3*2^2*6})-(\sqrt{3*2^2*10})+(\sqrt{6^2})-(\sqrt{6*10})

(2\sqrt{18})-(2\sqrt{30})+(6)-(\sqrt{60})

We can also rewrite 18 as 9 x 2 and 9 can be rewritten as 3^2 which will make the 3 come out.

60 can be rewritten as 15 x 4 and 4 can be rewritten as 2^2 which will make the 2 come out.

Let's rewrite this.

(2\sqrt{2*3^2})-(2\sqrt{30})+(6)-(\sqrt{15*2^2})

When a number comes out of a root, it has to be multiplied by the number that is already outside.

(2*3\sqrt{2})-(2\sqrt{30})+(6)-(2\sqrt{15})

Solve and eliminate parentheses.

6\sqrt{2}-2\sqrt{30}+6-2\sqrt{15}

6 0
3 years ago
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Bezzdna [24]

Answer:

The number is -100, Jill can think of something else, now.

Step-by-step explanation:

x = the number

x/4 - 20 = -45 {twenty less than one-fourth of the number is -45}

x/4 = -25 {added 20 to each side}

x = -100 {multiplied each side by 4}

5 0
3 years ago
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16) F(-3,-2), 1(-4, 3), A(-2, 3), M(1,-1)<br> to<br> I(-4, -3), A(-2, -3), M(1, 1), F(-3, 2)
pantera1 [17]

Answer:

(234/efr335)-k29504

Step-by-step explanation:

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