Answer:
w=4
Step-by-step explanation:
2(48)+2(8w)+2(6w)=208
1) Start by Distributing the value outside of the parenthesis:
96+16w+12w=208
2) Combine alike terms:
96+28w=208
3) Subtract 96 from both sides:
28w=112
4)Divide both sides by 28 to isolate w:
w=4
Let me know if you do not understand :)
We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
the first and third choices are both correct.
Answer:
3 x^3 y^4 sqrt(5x)
Step-by-step explanation:
sqrt(45x^7y^8)
We know that sqrt(ab) = sqrt(a)sqrt(b)
sqrt(45)sqrt(x^7) sqrt(y^8)
sqrt(9*5) sqrt(x^2 *x^2 * x^2* x) sqrt(y^2 *y^2 *y^2 *y^2)
We know that sqrt(ab) = sqrt(a)sqrt(b)
sqrt(9)sqrt(5) sqrt(x^2)sqrt(x^2) sqrt(x^2) sqrt(x) sqrt(y^2)sqrt(y^2)sqrt(y^2)sqrt(y^2)
3 sqrt(5) x*x*x sqrt(x) y*y*y*y
3 x^3 y^4 sqrt(5)sqrt(x)
3 x^3 y^4 sqrt(5x)
