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kakasveta [241]
2 years ago
7

How to do the foil method to solve (2r+3s)(2r-s)

Mathematics
1 answer:
lana [24]2 years ago
5 0
(2r+3s)(2r-s)=4r^2-3s^2+6rs-2rs=4r^2-3s^2+4rs
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What is the answer? and how would I solve this problem? (1+5)×(7−3)
TiliK225 [7]
Solve inside the parenthesis first:
1+5 = 6
7-3 = 4
then multiply the two
6 X 4

the answer is 24
7 0
2 years ago
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What is the line that passes through (2,4) and (3,8)
mihalych1998 [28]

Answer:

2, 4

Step-by-step explanation:

i just look at a graph

8 0
2 years ago
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Find three real numbers​ x, y, and z whose sum is 6 and the sum of whose squares is as small as possible. g
mart [117]
We're minimizing x^2+y^2+z^2 subject to x+y+z=6. Using Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(x+y+z-6)

with partial derivatives

\begin{cases}L_x=2x+\lambda\\L_y=2y+\lambda\\L_z=2z+\lambda\\L_\lambda=x+y+z-6\end{cases}

Set each partial derivative equal to 0:

\begin{cases}2x+\lambda=0\\2y+\lambda=0\\2z+\lambda=0\\x+y+z=6\end{cases}

Subtracting the second equation from the first, we find

2x-2y=0\implies x=y

Similarly, we can determine that x=z and y=z by taking any two of the first three equations. So if x=y=z determines a critical point, then

x+y+z=3x=6\implies x=y=z=2

So the smallest value for the sum of squares is 2^2+2^2+2^2=12 when (x,y,z)=(2,2,2).
8 0
3 years ago
Can someone explain why the ans is X=6? Its (x-6)
andrew-mc [135]

Answer:

because either x-6=0 or x+1=0

x-6=0

x=0+6

x=6     OR,

x+1=0

x=0-1

x=-1

Step-by-step explanation:

5 0
2 years ago
Find the zeros of g(x)=2x^2+32
expeople1 [14]

Answer:

x = 4i, − 4i

Step-by-step explanation:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x

x = 4i, − 4i

4 0
2 years ago
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