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Shtirlitz [24]
3 years ago
6

What is the area of a pentagon with the side length of 13 and apothem of 9?

Mathematics
1 answer:
GrogVix [38]3 years ago
6 0

Answer:

290.761

Step-by-step explanation:

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Answer:

2.-2m^4-6m^2+4m+9

3.-2m^4-6m^2-4m+9

Step-by-step explanation:

<em>In general we can write a polynomial in standard form as </em>

ax^n+bx^n^-^1+cx^n^-^2+...+px+q

<em>Given</em> 4m-2m^4-6m^2-4m+9

<em>Combine the like terms: 4m and -4m</em>

<em>4m-4m=0</em>

<em>We have 4m-4m=0</em>

<em>So, write the remaining terms</em>

-2m^4-6m^2+9+0

= -2m^4-6m^2+9

<em>This is in decreasing order of powers.</em>

<em>Hence the answer is the standard form is</em>

-2m^3-6m^2+9

<em>But in the given options, you can choose option 2 and option 3 are in standard form.</em>

<em>Because they are in decreasing order of powers.</em>

<em>In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.</em>

<em>-2m^4-6m^2+4m+9</em>

<em>-2m^4-6m^2-4m+9</em>

<em>I hope this helps you.</em>

<em>And please comment if I need to do corrections.</em>

<em>Please let me know if you have any questions.</em>

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