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DedPeter [7]
3 years ago
5

Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p

article is given by x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π. Are any of these points of intersection collision points? In other words, are the particles ever at the same place at the same time? If so, find the collision points.
Mathematics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t  

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t  = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

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Answer:

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Step-by-step explanation:

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c) If we multiply [eq1] above by -16 and add the constant on the right, we get the vertex form of the height equation:

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If you really need answers fast, a graphing calculator can give them to you in very short order (less than a minute).

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Step-by-step explanation:

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ZanzabumX [31]

Answer:

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