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kirill [66]
3 years ago
7

ONLY ANSWER IF YOU!! I WILL GIVE YOU BRAINLYEST!!

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Right square pyramid

Solve for lateral surface area

AL≈148.43

a Base edge  

6

h Height  

12

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C.

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X^2+ 17x+91=0<br> Help please!!
Morgarella [4.7K]

Answer:

x^2+17x+91=0

a = 1; b = 17; c = +91;

Δ = b2-4ac

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Step-by-step explanation:

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3 years ago
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nignag [31]
In word problems on topics of trigonometry, the terms of angle of depression and angle of elevation are very common. The angle of depression is used when the observer is above the point of reference. The angle made from the observer to the object is the angle of depression. To understand more clearly, refer to the attached picture.

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8 0
3 years ago
River C is 500 miles longer than River D. If the sum of their lengths is 5,560 miles, what is the length of each river?
AleksAgata [21]

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Please mark brainliest

8 0
3 years ago
Find the indefinite integral by using the substitution x = 4 sec(θ). (Use C for the constant of integration.) x2 − 16 x d
guapka [62]

Answer:

\frac{x^2-16}{2} + 16ln\frac{4}{x}  +16C

Step-by-step explanation:

Given the indefinite integral \int\limits{\frac{x^2-16}{x} } \, dx, using the substitute

x = 4 sec(θ)...1

The integral can be calculated as thus;

First let us diffrentiate the substitute function with respect to θ

dx/dθ = 4secθtanθ

dx =  4secθtanθdθ... 2

Substituting equation 1 and 2 into the integral function we will have;

\int\limits{\frac{(4sec \theta)^2-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{16sec^2 \theta-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{(16(sec^2 \theta-1)}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\from \ trig \ identity,\  sec^2 \theta - 1 = tan^\theta\\\\\int\limits{\frac{16 tan^2 \theta}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\\int\limits 16 tan^3 \theta d \theta\\\\

Find the remaining solution in the attachment.

3 0
3 years ago
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