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iragen [17]
3 years ago
11

Ball B, with a mass of 30kg, is moving to the left at -10 m/s. With what velocity should Ball A, with a mass of 10 kg, move to t

he right and collide with B, so that Ball A rebounds with a velocity of -30 m/s, and Ball B with velocity of 10 m/s, after the collision? Assume the collision to be perfectly elastic.
Use the formula for perfect elasticity. m1v1(initial) + m2v2(initial) = m1v1(final) + m2v2(final) m1 = mass of object 1, m2 = mass of object 2 v1 = velocity of object 1, v2 = velocity of object 2
Mathematics
1 answer:
tangare [24]3 years ago
5 0
Initially, Ball A of 10 kg will have velocity x, while Ball B of 30 kg has velocity -10 m/s.
After collision, Ball A will have a velocity of -30 m/s, while Ball B will have velocity 10 m/s. We assume their masses do not change.
(10 kg)(x m/s) + (30 kg)(-10 m/s) = (10 kg)(-30 m/s) + (30 kg)(10 m/s)
10x - 300 = -300 + 300
x = 30 m/s (to the right)
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6 0
4 years ago
Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen
Irina-Kira [14]
Hi there!

PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)

Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1

PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.

Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
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ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
8 0
4 years ago
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