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iragen [17]
4 years ago
11

Ball B, with a mass of 30kg, is moving to the left at -10 m/s. With what velocity should Ball A, with a mass of 10 kg, move to t

he right and collide with B, so that Ball A rebounds with a velocity of -30 m/s, and Ball B with velocity of 10 m/s, after the collision? Assume the collision to be perfectly elastic.
Use the formula for perfect elasticity. m1v1(initial) + m2v2(initial) = m1v1(final) + m2v2(final) m1 = mass of object 1, m2 = mass of object 2 v1 = velocity of object 1, v2 = velocity of object 2
Mathematics
1 answer:
tangare [24]4 years ago
5 0
Initially, Ball A of 10 kg will have velocity x, while Ball B of 30 kg has velocity -10 m/s.
After collision, Ball A will have a velocity of -30 m/s, while Ball B will have velocity 10 m/s. We assume their masses do not change.
(10 kg)(x m/s) + (30 kg)(-10 m/s) = (10 kg)(-30 m/s) + (30 kg)(10 m/s)
10x - 300 = -300 + 300
x = 30 m/s (to the right)
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Answer:

D,E

Step-by-step explanation:

hope I helped

4 0
3 years ago
Given f(x)=x+7 and g(x)=x-3 what is f(x)+g(x) ? A.2x+4 B.10x C.2x-7 D.-2x+10
Zinaida [17]
F(x)+g(x) = (x+7) + (x-3) =
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7 0
3 years ago
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A rectangular box is 6 inches wide 10 inches long and 2 inches tall how much wrapping paper is needed to cover the box exactly
stepladder [879]

Answer:

184 in²

Step-by-step explanation:

Given :

Width, w = 6 inches

Length, l = 10 inches

Height, h = 2 inches

To obtain how much wrapping paper is needed ; we take the surface area of the box

Surface area = 2(lw + lh + wh)

Surface area = 2((6*10) + (6*2) + (10*2))

Surface area = 2(60 + 12 + 20)

Surface area = 2(92)

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7 0
3 years ago
Using the line of best fit, estimate how may miles Jack ran the 10th week; show work.
Lapatulllka [165]
One way is to type it into your trusty TI and use the table from presing stat and then stat againg then calc then 4
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3 0
3 years ago
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A parking lot covers 32,420 square feet. What is its area to the nearest thousand feet? Explain how you round the number.
REY [17]
The thousands place (1000) is the fourth number to the left of the decimal, so round that one either up or down based on the number just one spot closer to the decimal, in this case, the hundreds place (100).

so we have 32,420

we can ignore the numbers that are going to become zeros as a result of the rounding . .

32,400

let's round 32,XXX either up or down based on the value in the hundreds place. if that value is 5 or greater, than we round up. if it is less than 5, than we round down.

4 is in the hundreds place, so we round down

32,000 is the answer
8 0
3 years ago
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