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alisha [4.7K]
2 years ago
10

How is the solution set of the sentence below described? X + 5 < 7

Mathematics
1 answer:
Crank2 years ago
4 0

Answer:

B. {All numbers less than 2}

Step-by-step explanation:

X + 5 < 7

Subtract 5 from each side

X + 5-5 < 7-5

x<2

All numbers less than 2

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Choose true or false for each statement about the equation (x+14)^1/2 = x+2
vladimir2022 [97]

Answer:

The answer is false

Hope this helps !

Mark me brainliest if I'm right :)

5 0
3 years ago
What is the slope of a line that is parallel to the line whose equation is y=4/5x-3
PolarNik [594]

Answer: 4/5

Step-by-step explanation: For a line to be parallel to another line there must be two conditions true.

Condition 1: Both lines must have the same slope (i.e the same x in the form y = mx + b)

Condition 2: Both lines must have different y-intercepts (i.e different b in the form y = mx + b)

Thus, if you are looking for the slope of the line parallel to y = 4/5x - 3, we can look at condition 1, and see that the slope should also be 4/5 for the other line.

3 0
2 years ago
Why are halves a good choice for benchmark fractions for 1 1/3
Natalka [10]

Answer and explanation:

Benchmark fractions are fractions that are used as references in measuring other fractions. They are easily estimated and so can be used in measuring more "specific" fractions such as 1/5, 7/9, 3/7, 1/3 etc. If I wanted to measure 1 1/3cm for instance using a calibrated ruler, having centimeter measurements, I would first find 1cm on the ruler and then find half of one centimeter. Seeing that half is bigger than 1/3 but close, I could then estimate 1/3 to be somewhere less than 1/2 but a bit close to it

3 0
3 years ago
∠1 and ∠2 are supplementary angles. If m∠1 = 77°, then m∠2 =
posledela

Answer:

B. 103°

Step-by-step explanation:

Supplementary angles add up to 180°, so we can find the measure of angle 2 by subtracting 77 from 180

180 - 77

= 103

So, m∠2 is 103°

7 0
2 years ago
Complete the table thanks in advance
inna [77]
Y = 1/2 x

for x = 0 → y = 1/2 · 0 = 0
for x = 2 → y = 1/2 · 2 = 1


   x      | 0 | 2 |
y=1/2x| 0 | 1 |


y = x + 3

for x = 0 → y = 0 + 3 = 3
for x = -3 → y = -3 + 3 = 0

    x    | 0 | 3 |
y=x+3|-3 | 0 |
6 0
3 years ago
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