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Umnica [9.8K]
2 years ago
13

What is the slope of a line that is parallel to the line whose equation is y=4/5x-3

Mathematics
1 answer:
PolarNik [594]2 years ago
3 0

Answer: 4/5

Step-by-step explanation: For a line to be parallel to another line there must be two conditions true.

Condition 1: Both lines must have the same slope (i.e the same x in the form y = mx + b)

Condition 2: Both lines must have different y-intercepts (i.e different b in the form y = mx + b)

Thus, if you are looking for the slope of the line parallel to y = 4/5x - 3, we can look at condition 1, and see that the slope should also be 4/5 for the other line.

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Which zero pair could be added to the function f(x)=x^2+12x+6 so that the function can be written in vertex form?
andrew11 [14]
<span>f(x) = x</span>² <span>+ 12x + 6  </span>→ y = x² + 12x + 6<span>

Let us convert the standard form into vertex form.

1) Complete the squares. Isolate x</span>² and x terms.
<span>y - 6 = x</span>² + 12x
<span>
2) Create the perfect square trinomial. Whatever number is added on one side must also be added on the other side. 

y - 6 + 36 = x</span>² + 12x + 36<span>
y + 30 = (x + 6)</span>²
<span>y = (x + 6)</span>² - 30  ← Vertex form
<span>
To check:

y = (x + 6) (x + 6) - 30
y = x</span>² + 6x + 6x + 36 - 30
<span>y = x</span>² + 12x + 6<span>

The zero that could be added to the given function is 36, -36</span>
4 0
3 years ago
What is the solution to the system of linear equations? y=4x and y-4x=0​
musickatia [10]

Answer:

  y = 4x; there are an infinite number of solutions

Step-by-step explanation:

Both equations describe the same relation between x and y. The system is "dependent", so has an infinite number of solutions. For any value of x, the solution is ...

  (x, y) = (x, 4x)

7 0
3 years ago
A particular geometric sequence has strictly decreasing terms. After the first term, each successive term is calculated by multi
Maksim231197 [3]

Answer:

6 possible integers

Step-by-step explanation:

Given

A decreasing geometric sequence

Ratio = \frac{m}{7}

Required

Determine the possible integer values of m

Assume the first term of the sequence to be positive integer x;

The next sequence will be x *  \frac{m}{7}

The next will be; x *  (\frac{m}{7})^2

The nth term will be x *  (\frac{m}{7})^{n-1}

For each of the successive terms to be less than the previous term;

then \frac{m}{7} must be a proper fraction;

This implies that:

0 < m < 7

<em>Where 7 is the denominator</em>

<em>The sets of </em>0 < m < 7<em> is </em>\{1,2,3,4,5,6\}<em> and their are 6 items in this set</em>

<em>Hence, there are 6 possible integer</em>

3 0
3 years ago
-2 • (-3)3 = ?<br><br> i really need help, I’m struggling so much in math.
Ronch [10]

Answer:

The answer would be 54

Step-by-step explanation:

6 0
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Verdich [7]

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Step-by-step explanation:

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