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Agata [3.3K]
3 years ago
9

Choose true or false for each statement about the equation (x+14)^1/2 = x+2

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

Answer:

The answer is false

Hope this helps !

Mark me brainliest if I'm right :)

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15 tickets in all 5x3
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A polynomial divided by a polynomial is a polynomial. always, sometimes, or never true?
Artemon [7]
I think it is always true. I am not sure but I hope I'm right
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3 years ago
Which value for the number makes the statement true?
umka21 [38]
A product is the result of multiplication.
A quotient is the result of division.
So you're trying to find the quotient of a number (x) and 5 that equals 8.

Try plugging in the answers. 
  x/5=8

A. x=4
  4/5=8  (Incorrect, 4 divided by 5 is 0.8)

B. x=8
  8/5=8  (Incorrect, 8 divided by 5 is 1.6)

C. x=40
  40/5=8  (Correct, 40 divided by 5 is 8)

D. x=80
  80/5=8  (Incorrect, 80 divided by 5 is 16)

So your answer is C. 40
The quotient of 40 and 5 is 8.
3 0
3 years ago
Hey.... sorry for that, are you still mad at me ?​
Digiron [165]

Answer:

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8 0
2 years ago
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For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
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