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marshall27 [118]
3 years ago
13

Anthony found a sweater on sale for 15% off! The discount price of the sweater before tax is $22.74. What is the regular price o

f the sweater before the discount?
Mathematics
1 answer:
kiruha [24]3 years ago
8 0

9514 1404 393

Answer:

  $26.75

Step-by-step explanation:

The after-discount price is 85% of the original price. So, the original price is ...

  0.85 × p = 22.74

  p = 22.74/0.85 = 26.75 . . . . . divide by the coefficient of p

The regular price is $26.75.

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The length of the segment from –3 to 0 on a number line is shown.
Andrei [34K]

Step-by-step explanation:

all are correct

this might help you

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3 years ago
Mahni plans to spend the next 12 weeks saving some of her income. She will save $x a week for the first 6 weeks and then $(2x −
levacccp [35]

Answer:

$3654

Step-by-step explanation:

7 0
3 years ago
How many ounces are in 4 pints?
nlexa [21]

Answer:

64 ounces are in 4 pints

Step-by-step explanation:

1 pint = 16 ounces

16 * 4 = 64

6 0
3 years ago
Circle O has a circumference of 36tt cm. what is length of the radius r
allochka39001 [22]

Answer:

5.73cm

Step-by-step explanation:

Given parameters:

Circumference of the circle = 36cm

Unknown

Length of the radius = ?

Lets represent the radius by r

Solution

The circumference of a circle is the defined as the perimeter of a circle. The formula is given as:

            Circumference of a circle = 2πr

Since the unknown is r, we make it the subject of the formula:

           r = \frac{circumference of the circle}{2π}

          r = \frac{36}{2 x 3.142} = \frac{36}{6.284} = 5.73cm

3 0
4 years ago
Read 2 more answers
If f(x)=8x then what is the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x=2 and x=6
Alina [70]

Answer:

A=128

Step-by-step explanation:

First of all we need to graph f(x)=8x, (First picture)

Now we have to calculate the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x_{1}=2 and x_{2}=6 ,

The area that we have to calculate is in pink (second picture).

The function is positive and the domain is [2,6] then we can calculate the area with this formula:

A=\int\limits^b_a {f(x)} \, dx,

In this case b=x_{2} , a=x_{1}

A=\int\limits^6_2 {8x} \, dx = 8\int\limits^6_2 {x} \, dx

The result of the integral is,

A=8\frac{x^{2}}{2}, but the integral is defined in [2,6] so we have to apply Barrow's rule,

<em>Barrow's rule:</em>

<em>If f is continuous in [a,b] and F is a primitive of f in [a,b], then:</em>

<em>\int\limits^b_a {f(x)} \, dx =F(b)-F(a)</em>

Applying Barrow's rule the result is:

A=8.\frac{6^{2} }{2}-8.\frac{2^{2} }{2}

A=8.\frac{36}{2} -8.\frac{4}{2}

A=144-16

A=128

6 0
3 years ago
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