Help would be much appreciated
1 answer:
Answer:
Figure is not accurate but i drew AE such that it is equal to BD and ED is equal to AB and AE is perpendicular to CD. And also ABDE is a rectangle.
Step-by-step explanation:
CD:AB
or, let CD be x
now
CD:AB= 1.5:1
or, x : 1.7 = 1.5 : 1
or, x/1.7 = 1.5/1
or, x = 2.6 m
CD = 2.6 m
ED=AB=1.7 m
now
CD = CE + ED
or, 2.6m =CE + 1.7m
or, CE = 2.6 m - 1.7 m
so, CE = 0.9 m
now
triangle CEA is a right angled triangle,
In triangle CEA, taking 52 as reference angle
tan52° = p/b
or,tan52° = CE/AE
or, tan52° = 0.9/AE
or, AE = 0.9/tan52°
so, AE = 0.7
now
AE = BD (given in the figure i uploaded)
so, BD = 0.7 m
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Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.
The minimum score required for an A grade is 83.