Answer:
Q10 is 13.64 cm3
Q 11 is 221 cm3
Step-by-step explanation:
volume is cross sectional area times height for Q 10
volume is length times width times height for Q 11
Volume=length X breadth X height
hence, volume= 9.6 X 5 X 7 cubic millimeters
which is equal to 336 cubic mm
3s + 135 = 4.5s + 45
Now move the variables and coefficients
135 = 1.5s + 45
And then the numbers
90 = 1.5s
Simplify
90/1.5 = 1.5s/1.5
60 = s
Hope this helps!
The true statement about her method would be to start at the origin. But you would go up 4 spaces you would go to the right 4 spaces.
-4(-5-b)=1/3(b+16) Multiply both sides by 3 to get rid of the fraction
-12(-5-b)=b+16 distribute the -12 to get rid of the parenthesis
60+12b=b+16 get the b on the left side and non b values to the right side
11b=-44 solve for b
b=-44/11 simplify the fraction
b=-4
3/5(t+18)=-3(2-t) multiply both sides by 5/3 to get rid of thefraction
t+18=-5(2-t) distribute the -5 to get rid of the parenthises
t+18=-10+5t get the t to the left side and non t values to the right
-4t=-28 solve for t
t=7
