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2 years ago

Can someone answer all of them? Tysm!

Mathematics

2 answers:

den301095 [7]2 years ago

8 0

1.) 1/12

2.) 2/13

3.) 8/41

4.) 1/4

5.) 11/74

6.) 2/35

7.) 15/58

8.) 5/18

9.) 1/7

10.) 1/13

stira [4]2 years ago

4 0

In a river bank

you can put the answers from the end

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A hospital uses cobalt-60 in its radiotherapy treatments for cancer patients. Cobalt-60 has a half-life of 7

NeTakaya

Answer:

We have 197 g of Co-60 after 18 months.

Step-by-step explanation:

We can use the decay equation.

$M_{f}=M_{i}e^{-\lambda t}$

Where:

M(f) and M(i) are the final and initial mass respectively
λ is the decay constant (ln(2)/t(1/2))
t(1/2) is the half-life of Co
t is the time at the final amount of m

$M_{f}=228e^{-\frac{ln(2)}{7} 1.5}$

$M_{f}=197\: g$

Therefore, we have 197 g of Co-60 after 18 months.

I hope it helps you!

4 0

3 years ago

Express 8 sin^2x - 10sinxcosx in the form a+b sin(2x+c).

ladessa [460]

8 sin2x - 10sinxcosx = 8*2sinXcosX-10sinXcosX = 16sinXcosX - 10sinXcosX = 6sinXcosX=3sin2x

7 0

3 years ago

You are researching two glaciers.the first glacier flows at a rate of 75 meters in 3 days.the second glacier flows at a rate of

podryga [215]

Answer:

$1.3\ days$

Step-by-step explanation:

step 1

Find the units rate of the first glacier

$\frac{75}{3}=25\frac{meters}{day}$

using proportion

$\frac{25}{1}\frac{meters}{day}=\frac{200}{x}\frac{meters}{days}\\ \\x=200/25\\ \\x=8\ days$

step 2

Find the units rate of the second glacier

$\frac{107.5}{5}=21.5\frac{meters}{day}$

using proportion

$\frac{21.5}{1}\frac{meters}{day}=\frac{200}{x}\frac{meters}{days}\\ \\x=200/21.5\\ \\x=9.3\ days$

step 3

Find the difference

$9.3\ days-8\ days=1.3\ days$

4 0

2 years ago

What is the solution to 2(-4x+1)=2/3(x+2)

Rzqust [24]

Hello!

The answer to your problem is: $x=1/13$

Simplify both sides of the equation

$(2)(-4x)+(2)(1)=(2/3)(x)+(2/3)(2)$ $(Distribute)$

$-8x+2=2/3x+4/3$

Subtract 2/3x from both sides

$-8x+2-2/3x=2/3+4/3-2/3x$

$-26x+2=4/3$

Subtract 2 from both sides

$-26/3x+2-2=4/3-2$

$-26/3=-2/3$

Multiply both sides by 3/(-26)

$(3/26)*(-26/3x)=(3/-26)*(-2/3)$

Get your answer

$x=1/13$

Hope This Helps!

8 0

3 years ago

F(x) = 2x^2 - 3x, calculate f(x+h)-f(x) / h

kvasek [131]

First plug in (x+h) for x in the function.
f(x+h)= 2(x-h)^2-3(x-h) = 2(x^2-2xh+h^2)-3x-3h =
2x^2-4xh+2h^2-3x-3h - 2x^2 +3x =
(-4xh +2h^2-3h)/h
-4x +2h-3

6 0

3 years ago

Can someone answer all of them? Tysm!​

Can someone answer all of them? Tysm!