Question

Is the given function continuous at x=1?

Answer 1

Answer:

The answer is "Option C".

Step-by-step explanation:

Given:

$\to f(x)=2x^2-3x+1\\\\when \ x=1\\\\\to f(1)= 2(1)^2-3(1)+1\\\\\to f(1)= 2(1)-3+1\\\\\to f(1)= 2-3+1\\\\\to f(1)=-1+1\\\\\to f(1)=0$

That's why choice C is correct.